Answer: 12.56 feet
Step-by-step explanation:
Given: The width of the circular path= 2 feet
The inner diameter of circular path= 150 feet
Therefore, the inner radius of circular path=[tex]\frac{150}{2}=75\ ft[/tex]
Now, the outer radius= 75+2=77 feet
We know that the circumference= [tex]2\pi r[/tex]
Inner circumference= [tex]2\pi 75=150\pi[/tex]
Outer circumference= [tex]2\pi 77=154\pi[/tex]
The difference= [tex]154\pi-150\pi=4\pi=4\times3.14=12.56\ feet[/tex]
Hence, the outer edge of the path is 12.56 feet farther than the inner edge
