Answer:
B. 100 J
Explanation:
The change in potential energy of an object is given by:
[tex]\Delta U= W \Delta h[/tex]
where
W is the weight of the object
[tex]\Delta h[/tex] is the variation of height of the object
In this problem, the weight of the baseball is W=10 N, while the variation of height is [tex]\Delta h=10 m[/tex]. So, the increase in potential energy of the ball is
[tex]\Delta U=(10 N)(10 m)=100 J[/tex]
