hi please help with a few (mean, median) math questions!

1. A student wants to report on the number of movies her friends watch each week. The collected data are below:

1ST PIC ATTACHMENT

Which measure of center is most appropriate for this situation and what is its value?
Median; 1.5
Median; 3
Mean; 1.5
Mean; 3

2. If the outliers are not included, what is the mean of the data set?

76, 79, 80, 82, 50, 78, 83, 79, 81, 82

77
78
79
80

3. Given the box plot, will the mean or the median provide a better description of the center?

2ND PIC ATTACHEMENT

The mean, because the data distribution is symmetrical
The mean, because the data distribution is skewed to the left
The median, because the data distribution is skewed to the left
The median, because the data distribution is skewed to the right

4. When the outliers are removed, how does the mean change?

3RD PIC ATTACHEMENT

The mean remains the same.
The mean decreases by 2.
The mean increases by 2.
There are no outliers.

Question

ilovegerman ilovegerman

25-01-2016
Mathematics

contestada

hi please help with a few (mean, median) math questions!

1. A student wants to report on the number of movies her friends watch each week. The collected data are below:

1ST PIC ATTACHMENT

Which measure of center is most appropriate for this situation and what is its value?
Median; 1.5
Median; 3
Mean; 1.5
Mean; 3

2. If the outliers are not included, what is the mean of the data set?

76, 79, 80, 82, 50, 78, 83, 79, 81, 82

77
78
79
80

3. Given the box plot, will the mean or the median provide a better description of the center?

2ND PIC ATTACHEMENT

The mean, because the data distribution is symmetrical
The mean, because the data distribution is skewed to the left
The median, because the data distribution is skewed to the left
The median, because the data distribution is skewed to the right

4. When the outliers are removed, how does the mean change?

3RD PIC ATTACHEMENT

The mean remains the same.
The mean decreases by 2.
The mean increases by 2.
There are no outliers.

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shininggirl2005 shininggirl2005 · Answer 1 · 2016-01-25T20:05:02+01:00

1.rearrange your data from least to greatest:
0,0,1,1,2,2,2,14

middle is 1 and 2 ... so median is 1+2/2= 1.5 and it is the median not the mean
2.I believe the only outlier is 50. Finding the mean would be 80.11.
The answer would be D
3.D. Mean always goes toward the skewness due to outliers.
Median is minimally affected by outliers.
4.We remove an outlier because we can simply assume that there was some type of extreme experimental error, or something went wrong. The mean shouldn't be effected that much, but the median will be greatly effected.