how many moles are in 1.1 grams of fecl3

Molar mass of FeCl3 = 162.2 g/mol

1 mole FeCl3 -------------- 162.2 g
mole FeCl3 ---------------- 1.1 g

moles = 1.1 / 162.2

= 0.00678 moles

hope this helps!.

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raquecgomez raquecgomez · Answer 2 · 2019-08-26T03:45:14+02:00

Answer:

[tex]6.83.10^{-3} mol FeCl_{3}[/tex]

Explanation:

We have to find the molar mass of the compound.

We must multiply the atomic mass of each element of the compound by the number of atoms of each one

[tex]FeCl_{3}[/tex]

molar mass [tex]FeCl_{3}[/tex]

[tex]Fe= 56g/mol\\Cl= 35g/mol[/tex]

[tex]FeCl_{3}= 56g/mol+3(35g/mol)=161g/mol[/tex]

We know that in 1 mol of [tex]FeCl_{3}[/tex] it has a mass of 161g.

Now we can find out how many moles of [tex]FeCl_{3}[/tex] are in 1.1 g.

[tex]161g FeCl_3\longrightarrow 1 mol FeCl_3\\ 1.1g FeCl_3\longrightarrow x\\ x=\frac{1.1g FeCl_3.1 molFeCl_3}{161 g FeCl_3} = 6.83.10^{-3} mol FeCl_{3}[/tex]