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The trait of “freckles” is dominant and represented by A. No freckles is recessive and represented by a. A researcher crossed two individuals, one homozygous dominant and the other heterozygous for freckles. Based on the data in the Punnett square, the researcher concluded that all offspring would have dominant as well as the recessive alleles. What comment would you make about his conclusion?

Respuesta :

lisetteilozo
Not all of them would have freckles with the recessive trait because two of them would be homozygous recessive you see this if you do a punnet square
gamingdragon09
Well, let's start by solving the punnett square to prove if the researcher is correct, or not. Homozygous dominant is; AA. Heterozygous is; Aa.
    _A___A_
A | AA | AA |
   |------|------|
a |  Aa | Aa |
(sorry if that's not a good punnett square)

So the possible solutions are AA, AA, Aa, Aa

The researchers conclusion is incorrect. Although the offspring all have dominant alleles, not all of them will have a recessive allele.

Hope this helps!

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