Respuesta :
The lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches
Enter the z-score of a trout with a length of 28.2 inches.
Formula to find z score is
[tex]z = \frac{length - mean}{standard deviation}[/tex]
Length = 28.2, mean = 30 , standard deivation = 4.5
[tex]z = \frac{28.2- 30}{4.5}[/tex]
z = -0.4
So z-score = -0.4
