Respuesta :

liz33312
I presume the question is 125^(8x - 2) = 150 ?
If so, lg (has a base of 10) both sides of the equation,
lg 125^(8x - 2) = lg 150
<Bring the power down to the left, using formulae of lg (a)^b = b × lg a>
=> (8x - 2) × lg 125 = lg 150
=> (8x - 2) × lg 5^3 = lg 150
=> 3(8x - 2) × lg 5 = lg 150
=> (24x - 6) × lg 5 = lg 150
=> 24x - 6 = lg 150 ÷ lg 5
=> 24x = (lg 150 ÷ lg 5) + 6
=> x = [(lg 150 ÷ lg 5) + 6] ÷ 24
=> x ~ 0.379 (rounded off to 3 significant factors)

Hope this helps! :)

Answer:

- 0.1069

Step-by-step explanation:

Take the log base 10 of both sides of the equation:  

( 9x + 2 ) ( log 125 ) = log 150  

9x + 2 = log 150 / log 125  

9x = log 150 / log 125 - 2  

9x = - 0.962239 - 2 = - 2.962239  

x = ( - 2.962239 ) / ( 9 ) = - 0.1069

Otras preguntas