Respuesta :

1 mole of any gas under STP has volume 22.4 L,
we have 2 mole of gas, so volume of container should be 2*22.4 L= 44.8 L
sebassandin

Answer:

V=44.8L

Explanation:

Hello,

This problem can be solved by using the ideal gas equation:

[tex]PV=nRT[/tex]

Nonetheless, we've got two different gases, nitrogen and neon, whose total moles turn out into 2 mol and the STP conditions which are 1 atm and 0 ºC, thus, the volume that accounts for the container's size is computed via:

[tex]V=\frac{2mol*0.082 \frac{atm*L}{mol*K} * 273.15K}{1atm} \\V=44.8L[/tex]

Best regards.

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