The length of a simple pendulum with period 11.5 s = 32.86 m
Given data :
period ( T ) = 11.5 secs
acceleration due to gravity ( g ) = 9.8 m/s²
we will apply the formula below
[tex]T = 2\pi \sqrt{\frac{L}{g} }[/tex]
Therefore L = [tex]\frac{T^{2}g }{4\pi ^{2} }[/tex]
= ( 11.5 )² * 9.8 / 4 * (3.14)²
= 132.25 * 9.8 / ( 39.4384 )
= 32.86 m
Hence the length of a simple pendulum with period 11.5 s = 32.86 m
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