Respuesta :
rate=[a]*([b]^2)*([c]^(1/2)]
rate=[2a]*([b]^2)*([2c]^(1/2)]= 2*(2^(1/2)[a]*([b]^2)*([c]
it increases times 2*(2^(1/2)=2√2
rate=[2a]*([b]^2)*([2c]^(1/2)]= 2*(2^(1/2)[a]*([b]^2)*([c]
it increases times 2*(2^(1/2)=2√2
If the concentrations of a and c are doubled and b remains the same of the given reaction, then rate increases by 2√2 times.
How do we define rate of reaction?
Rate of any reaction is directly proportional to the concentration of the reactant with raise to their respective coefficients.
According to the question, initial rate of the reaction is:
Rate(1) = k[tex][a][b]^{2}[c]^{1/2}[/tex]
If concentration of a & c becomes 2a and 2c respectively, then
Rate(2) = k[tex][2a][b]^{2}[2c]^{1/2}[/tex]
Rate(2) = 2√2[tex][a][b]^{2}[c]^{1/2}[/tex]
Rate(2) = 2√2Rate(1)
Hence, rate of the reaction increases by 2√2 times.
To know more about rate of reaction, visit the below link:
https://brainly.com/question/8139015
