Answer : The Lewis structure for 3 nitrogen-containing compounds [tex](NO_2,NH_3\text{ and }HNO_3)[/tex] are shown below.
Explanation :
Lewis-dot structure : Lewis-dot structure shows the bonding between the atoms of a molecule and also shows the unpaired electrons present in the molecule.
(1) The given molecule is, nitrogen dioxide.
As we know that nitrogen has '5' valence electrons and oxygen has '6' valence electron.
Therefore, the total number of valence electrons in nitrogen dioxide, [tex]NO_2[/tex] = 5 + 2(6) = 17
According to Lewis-dot structure, there are 8 number of bonding electrons and 9 number of non-bonding electrons.
(2) The given molecule is, ammonia.
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electron.
Therefore, the total number of valence electrons in ammonia, [tex]NH_3[/tex] = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(3) The given molecule is, nitric acid.
As we know that nitrogen has '5' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electron.
Therefore, the total number of valence electrons in nitric acid, [tex]HNO_3[/tex] = 1 + 5 + 3(6) = 24
According to Lewis-dot structure, there are 10 number of bonding electrons and 14 number of non-bonding electrons.
The Lewis structure for 3 nitrogen-containing compounds [tex](NO_2,NH_3\text{ and }HNO_3)[/tex] are shown below.
