Respuesta :
f(x) = x + 1
------
b
g(x) = cx - d
flip values of x and y in each equation, then solve for y:
x = y + a
-------
b
y = a - bx
``````````````````````````````````````````````````````````
x = cy - d
y = x + d
-------
c
------
b
g(x) = cx - d
flip values of x and y in each equation, then solve for y:
x = y + a
-------
b
y = a - bx
``````````````````````````````````````````````````````````
x = cy - d
y = x + d
-------
c
Answer:
[tex]a = 2; \ d = 2; \ c=1; \ b=1[/tex]
Step-by-step explanation:
Two functions are inverse where their composition results in a variable only:
[tex]f(g(x))=x[/tex]
So, we have to insert the right numbers in place of letters a, b, c and d, to fulfil this definition. Those value would be: [tex]a = 2; \ d = 2; \ c=1; \ b=1[/tex]
Replacing these values, we have:
[tex]f(x)=x+2[/tex]
[tex]g(x)=1x-2=x-2[/tex]
Applying the composition [tex]f(g(x))[/tex]:
[tex]f(g(x))=\frac{cx-d+a}{b}[/tex]
We observe that with this values, these functions are inverse, because it composition results x.
[tex]f(g(x))=\frac{1x-2+2}{1}=x[/tex]
Therefore, the values are [tex]a = 2; \ d = 2; \ c=1; \ b=1[/tex]