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Which equation results from applying the secant and tangent segment theorem to the figure?

12(a + 12) = 10^2
10 + 12 = a^2
10(a + 10) = 12^2
10(12) = a^2

Which equation results from applying the secant and tangent segment theorem to the figure 12a 12 102 10 12 a2 10a 10 122 1012 a2 class=

Respuesta :

carlosego
1. You must apply the Secant and Tangent segment theorem, which establishes:

 Tangent²=(The whole secant segment)(External secant segment)

 2. The whole secant segment is: AD=a+12

 3. The external secant segment is: BD=10

 4. The tangent segment is: DE=12

 5. Then, you have:

 DE²=ADxBD
 12²=(a+10)10
 10(a+10)=12²

 6. Therefore, the answer is the third option: 10(a+10)=12²
abidemiokin

The equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

Secant theorem;

According to the secant and tangent segment theorem, the square of the tangent line is equal to the product of the secant segments. Mathematically;

Tangent² = whole secant segment × External secant segment

DE² = AD × BD

Given

DE = 12

AD = a+10

BD = 10

Substitute into the formula:

12²  = 10(a+10)

Hence the equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

learn more on secant and tangent segment theorem here: https://brainly.com/question/10732273

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