Respuesta :

CastleRook
suppose one of the roots is a the second is 2a. The factors will be:
(x-a) and (x-2a)
thus
(x-a)(x-2a)=x^2+6x+q
x^2-xa-2ax+2a^2=x^2+6x+q
taking corresponding terms we shall have:
-2ax=6x
solving for a we get
-2a=6
thus
a=-3
but
q=2a^2
substituting the value of a we get:
q=2(-3)^2
q=2*9
q=18
VirαtKσhli

Answer:

q = 18 , roots = -3&-6

Step-by-step explanation:

Let :-

  • First root = x
  • Second root = 2x

We know ,

  • Sum of roots = -b/a
  • x + 2x = -6/1
  • 3x = -6
  • x = -3

And ,

  • Product of roots = c/a
  • x * 2x = q
  • 2x²= q
  • q = 2* -3²
  • q = 2* 9
  • q = 18

Roots :-

  • x = -3
  • 2x = -6