Answer:
Step-by-step explanation:
X, the mean weight of passengers is N(180.2, 3838)
No of passengers n = 4040
std error = STd dev/ sqrt n
= 60.38
The probability that the aircraft is overloaded is 0.9920; since this is a greater than 50% chance, the pilot should either reduce the number of passengers on the plane or require them to reduce their baggage.
The z-score for this is given by
z = (X-μ)/σ = (169-180.2)/60.38 = -11.2/60.38 = -0.02
Using a z-table
P(Z<-0.02) = 0.0080
Prob for aircraft to be overloaded
= P(Z>-0.02)
=1-0.0080
=0.9920