Respuesta :
Answer: About 21.64% of the fruit will be between 642 and 657 grams.
To solve this problem, we will have to find the probability for each z-score on the normal distribution. Then, subtract them to find the difference.
Lower End:
-9/27 = -0.33 for the z-score which is a probability of 0.3707
Upper End:
6/27 = 0.22 for the z-score which is a probability of 0.5871.
0.5871 - 0.3707 = 0.2164
Or about 21.64%
To solve this problem, we will have to find the probability for each z-score on the normal distribution. Then, subtract them to find the difference.
Lower End:
-9/27 = -0.33 for the z-score which is a probability of 0.3707
Upper End:
6/27 = 0.22 for the z-score which is a probability of 0.5871.
0.5871 - 0.3707 = 0.2164
Or about 21.64%
The probability of mean weight [tex]642[/tex] gram is [tex]p=0.0990[/tex]
The probability of mean weight [tex]657[/tex] gram is [tex]p=0.9946[/tex]
Given Equation:
Mean [tex]=651[/tex]
Standard deviation [tex]=27[/tex]
n[tex]=49[/tex]
The general form of,
[tex]z=\frac{x -\mu}{\sigma\ /\sqrt{n} }[/tex]
Probability of [tex]657[/tex]:
By given,
[tex]x=642\\\sigma=27\\n=49\\\mu = 651\\[/tex]
Substitute the values in the general form,
[tex]z=\frac{642-651}{27/\sqrt{49} } \\\\z=\frac{-9}{27/7} } \\\\z=\frac{-9}{3.86} \\\\z=-2.331[/tex]
[tex]p=0.0990[/tex]
Probability of [tex]657[/tex]:
By given,
[tex]x=657\\\sigma=27\\n=49\\\mu = 651\\[/tex]
Substitute the values in the general form,
[tex]z=\frac{657-651}{27/\sqrt{49} } \\\\z=\frac{6}{27/7} } \\\\z=\frac{6}{3.86} \\\\z=1.55[/tex]
[tex]p=0.9946[/tex]
For more information,
https://brainly.com/question/9334808