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The area of a trapezoid is 69.6 in2 and its altitude is 8.7 in. Find the perimeter of the trapezoid if the sum of its legs is equal to the sum of its bases.

Respuesta :

To answer this you Will use the area of a trapezoid formula.

A = 1/2h(b1 + b2)
69.6 = 1/2 x 8.7(b1 + b2)
69.6 = 4.35(b1 + b2)
16 = (b1 + b2) - the sum of the bases

16 in = the sum of the legs and the sum of the bases

16 + 16 = 32 inches

The perimeter is 32 inches.

A trapezoid is a quadrilateral having one set of opposing sides that are parallel to each other.  The perimeter of the trapezoid is equal to 32 inches.

What is a trapezoid?

A trapezoid is a quadrilateral having one set of opposing sides that are parallel to each other. It can have right angles (a right trapezoid) and congruent sides (isosceles), but neither is necessary.

As is mentioned that the area of the trapezoid is 69.6 in², while its altitude is 8.7 inches. Therefore, the sum of the bases of the trapezoid can be written as,

[tex]\rm \text{Area of trapezoid} = \dfrac{1}{2} \times (Base_1 + Base_2) \times Altitude[/tex]

[tex]69.6 = \dfrac{1}{2} \times (b_1 + b_2) \times 8.7\\\\(b_1 +b_2) = 16\rm\ inches[/tex]

Now, it is mentioned that the sum of the legs of the trapezoid is equal to the sum of its bases. Therefore, the perimeter of the trapezoid is,

[tex]\text{Perimeter of Trapezoid} = (\text{Sum of its bases}) +(\text{Sum of its legs})\\\\\text{Perimeter of Trapezoid} = 16+16 = 32\rm\ inches[/tex]

Hence, the perimeter of the trapezoid is equal to 32 inches.

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