A natural law of decay is [tex]y= 2e^{-0.5x}[/tex] Draw a graph for this law for values of x from x = -4 to x = 4. From the graph:

A)Find the gradient of the curve at x = -3 and x = 0.5 by differentiation and by drawing a tangent to the curve.
B)Compare your two solutions for these gradients.

The graph the method of solution should look familiar. It is your other question but with different numbers.

A) y' = -0.5*(2e^(-0.5x)) = -e^(-0.5x)
.. Gradients and tangent points are in the table with the graph.

B) Same answer as previously. The second graph is provided for your enjoyment in doing this step.
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A natural law of decay is [tex]y= 2e^{-0.5x}[/tex] Draw a graph for this law for values of x from x = -4 to x = 4. From the graph: A)Find the gradient of the curve at x = -3 and x = 0.5 by differentiation and by drawing a tangent to the curve. B)Compare your two solutions for these gradients.

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A natural law of decay is [tex]y= 2e^{-0.5x}[/tex] Draw a graph for this law for values of x from x = -4 to x = 4. From the graph:

A)Find the gradient of the curve at x = -3 and x = 0.5 by differentiation and by drawing a tangent to the curve.
B)Compare your two solutions for these gradients.