A game uses the two spinners shown in the image. What is the probability that you will spin "East" and "1"

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babadnd babadnd · Answer 1 · 2018-03-26T01:43:37+02:00

1/32 because 1/4 is the probability for the first one and then 1/8 for the next one. 4 times 8 = 32 so there is a 1 in 32 chance

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virtuematane virtuematane · Answer 2 · 2019-06-11T09:32:33+02:00

The probability that you will spin "East" and "1" is:

[tex]\dfrac{3}{32}[/tex]

As we know that the spinning of the first wheel is independent of the outcome of the spinning of the second wheel.

Let A denote the event of East.

B denote the event of 1 .

Let P denote the probability of an event.

A∩B denote the event of East and 1.

We are asked to find P(A∩B)

We know that:

P(A∩B)=P(A)×P(B)

( When the events A and B are independent )

From the image we have:

P(A)=1/4

and P(B)=3/8

( Since there are 3 '1' in the spinner out of total 8 outcomes)

Hence we get:

[tex]P(A\bigcap B)=P(A)\times P(B)\\\\\\P(A\bigcap B)=\dfrac{1}{4}\times \dfrac{3}{8}\\\\\\P(A\bigcap B)=\dfrac{3}{32}[/tex]