The volume of a triangular pyramid is given by the equation [tex]A= \frac{1}{6}bh_1 h_2 [/tex] where b is the length of the base of the triangle on the base of the pyramid, h_1 is the length of the height of that triangle, and h_2 is the height of the pyramid. Set this equal to 100 and plug in random values for 2 out of the three variables. Do this twice to get two different pyramids with the same volume. For example, set b to 6 and h_2 to 10, and you get h_1 = 10. Set b to 12 and h_2 to 10 and you get h1 = 5. These are just two of the possible dimensions of the pyramid.
