Answer:
The dimensions of the rectangle is:
12 units × 8 units
Step-by-step explanation:
We are given coordinates of rectangle ABCD by:
A(-10,2) , B(2,2) , C(2,-6) and D(-10,-6)
The length of the given rectangle is same as length of AB.
By using distance formula we will calculate the length of segment AB.
[tex]Length\ AB=\sqrt{(2-(-10)^2+(2-2)^2}\\\\\\Length\ AB=\sqrt{12^2+0^2}\\\\\\Length\ AB=12\ units[/tex]
and the width of rectangle is same as length of segment BC.
[tex]Length\ BC=\sqrt{(2-2)^2+(-6-2)^2}\\\\\\Length\ BC=\sqrt{0^2+8^2}\\\\\\Length\ BC=8\ units[/tex]
Hence, the dimensions of rectangle ABCD is:
12 units× 8 units
