If what you are looking for in part A is the number of solutions for the following
9x² - 16x + 60 = 0 then the determinant defined by
[tex] \sqrt{ b^{2}-4ac } [/tex] would be:
[tex] \sqrt{( -16)^{2} -4(9)(60)} [/tex] and this produces a negative value under the radical. Therefore, there would be no real solutions to this quadradic
For Part B: the best solution strategy would be factoring as such:
4x² + 8x - 5 = (2x - 1)(2x + 5) and setting each binomial factor equal to "0" and solving, you find your solutions to be x = 1/2 and x = -5/2
