Answer: 0.4920238
Step-by-step explanation:
Given: z is a standard normal variable.
We know that probability of z lies lies between two values a and b is given by :-
[tex]P(a<z<b)=P(z<b)-P(z<a)[/tex]
Now, the probability that z lies between -2.41 and 0 is given by :-
[tex]P(-2.41<z<0)=P(z<0)-P(z<-2.41)\\\\\Rightarrow\ P(-2.41<z<0)=0.5-0.0079762=0.4920238[/tex] [By using z-table for standard normal distribution]
Hence, the probability that z lies between -2.41 and 0 = 0.4920238
