Current is equal to the quantity of charge, q, passing through a wire in a time period, t. So [tex]current = I = \frac{q}{t} [/tex].
1 ampere (A) is equal to 1 coulomb (C), a measurement of charge, over 1 second (s), a measurement of time.
You are told that the charge, q = 12.0 C and the time, s = 4.0 s. Plug these values into the equation for current:
[tex]I = \frac{q}{t}\\
I = \frac{12.0\:C}{4.0\:s} \\
I = 3.0 \:A
[/tex]
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Answer: The current is 3.0 A.
