Respuesta :
Data Given:
Mass of H₂C₂O₂.2H₂O = 2.38 g
M.mass of H₂C₂O₂.2H₂O = 126 g/mol
Volume = 300 ml = 0.3 dm³
Solution:
Molarity is given as,
Molarity = Moles / Vol. of Sol.
Or,
Molarity = (Mass / M.mass) × (1 / Vol)
Putting Values,
Molarity = ( 2.38 g ÷ 126 g/mol ) × ( 1 ÷ 0.3 dm³ )
Molarity = 0.063 mol/dm³
Mass of H₂C₂O₂.2H₂O = 2.38 g
M.mass of H₂C₂O₂.2H₂O = 126 g/mol
Volume = 300 ml = 0.3 dm³
Solution:
Molarity is given as,
Molarity = Moles / Vol. of Sol.
Or,
Molarity = (Mass / M.mass) × (1 / Vol)
Putting Values,
Molarity = ( 2.38 g ÷ 126 g/mol ) × ( 1 ÷ 0.3 dm³ )
Molarity = 0.063 mol/dm³
Taking into account the definition of molarity, the molarity of the solution is 0.063 [tex]\frac{moles}{liter}[/tex].
Molarity or Molar Concentration is a concentration measure that indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
[tex]molarity=\frac{amount of moles of solute}{volumen of the solution}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case, the solution contains 2.38 g of H₂C₂O₄.2H₂O. Being the molar mass of compound 126 g/mole, that is, the amount of mass that the compound contains in one mole, the number of moles that 2.38 g contains is calculated as:
[tex]2.38 gramsx\frac{1 mole}{126 grams} = 0.0189 moles[/tex]
Then, with the total volume being 300 mL = 0.300 L (where 1000 mL = 1L), the molarity is calculated as:
[tex]molarity=\frac{0.0189 moles}{0.300 L}[/tex]
molarity= 0.063 [tex]\frac{moles}{liter}[/tex]
Finally, the molarity of the solution is 0.063 [tex]\frac{moles}{liter}[/tex]
Learn more about molarity with this example: brainly.com/question/15406534?referrer=searchResults