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atski
You can use Avogradro's number. Periodic table's name for gold is Au. Mo

[tex]3.47 * 10^{23} atoms Au * \frac{1 mol Au}{6.022*10^{23} atoms Au} *\frac{196.96657 g Au}{1 mol Au} = 113.496180322g[/tex]

There are 3 sig figs. 

113 g Au

Answer: 114.26 grams

Explanation: According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadros number}}[/tex]

[tex]\text{Number of moles}=\frac{3.47\times 10^{23}}{6.023\times 10^{23}}=0.58moles[/tex]  

Mass of the gold coin=[tex]{\text {number of moles}}\times {\text {Molar mass of Au}}=0.58\times 197g/mol=114.26g[/tex]

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