Respuesta :
Given Data:
P₁ = 122 atm
P₂ = 112 atm
V₁ = 113 L
V₂ = ?
Solution:
Let suppose the gas is acting ideally. According to Ideal gas equation, keeping the temperature constant,
P₁ V₁ = P₂ V₂
Solving for V₂,
V₂ = P₁ V₁ / P₂
Putting Values,
V₂ = (122 atm × 113 L) ÷ 112 atm
V₂ = 113 L
Converting Volume to Moles,
As,
22.4 L is occupied by = 1 mole of He gas
So,
113 L will occupy = X moles of He gas
Solving for X,
X = (113 L × 1 mole) ÷ 22.4 L
X = 5.04 Moles of He
P₁ = 122 atm
P₂ = 112 atm
V₁ = 113 L
V₂ = ?
Solution:
Let suppose the gas is acting ideally. According to Ideal gas equation, keeping the temperature constant,
P₁ V₁ = P₂ V₂
Solving for V₂,
V₂ = P₁ V₁ / P₂
Putting Values,
V₂ = (122 atm × 113 L) ÷ 112 atm
V₂ = 113 L
Converting Volume to Moles,
As,
22.4 L is occupied by = 1 mole of He gas
So,
113 L will occupy = X moles of He gas
Solving for X,
X = (113 L × 1 mole) ÷ 22.4 L
X = 5.04 Moles of He