From the function given by f(x)=(x+5)(x-3), the true statements will be as follows:
the roots are x=-5 and x=3,
thus the x-intercepts are at (-5,0) and (3,0)
f(x)=(x+5)(x-3)=x^2+2x-15,
setting x=0, f(x)=0^2+2(0)-15=-15,
thus the y-intercept is at (0,-15)
from f(x)=x^2+2x-15, we see that coefficient of x^2 is positive, thus the graph has a relative maximum.
