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Provide an appropriate response. in a game, you have a 1/36 probability of winning $94 and a 35/36 probability of losing $8. what is your expected value

Respuesta :

calculista
We can find this by adding together the probabilities times the values of each probability, so it's:
 EV=P1*V1+P2*V2
where
EV-------> is the expected value
P1-------> (1/36)
V1-------> $94
P2------> (35/36)
V2------> -$8

so
 EV=(1/36)*94+(35/36)*(-8)-----> (94/36)+(-280/36)-----> -186/36---> -5.17

EV=-$5.17

the answer is
the expected value is EV=-$5.17
Dieguez

Answer:

-5.17

Step-by-step explanation:

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