the length of a rectangle is 4 meters less than twice its width. The area of the rectangle is 70m2. Find the dimensions of the rectangle

If the width = x m then the length = 2x - 4 m

Area = x(2x - 4) = 70

2x^2 - 4x - 70 = 0

2x^2 - 14x + 10x - 70 = 0

2x(x - 7) + 10(x - 7) = 0

(2x + 10)(x - 7) = 0
x = 7 or -5 ( ignore negative)
width = 7 m and length = 10 m answer

Answer Link

ewomazinoade ewomazinoade · Answer 2 · 2021-10-26T13:13:14+02:00

The dimensions of the rectangle are 10 meters and 7 meters.

A rectangle is a figure that has four sides.

The area of a rectangle = length x width

Let width be represented w

Length = 2w - 4

Area = 70

w x (2w - 4) = 70

2w² - 4w = 70

Divide the equation by 2

w² - 2w = 35

w² - 2w - 35 = 0

The factorisation method would be used to determine the factors of -35w² that add up to -2w. The factors are -7w and 5w

(w² + 5w) (-7w - 35) = 0

w(w + 5) -7(w + 5) = 0

w - 7 = 0

w = 7

w + 5 = 0

w = - 5

The dimensions of a rectangle cannot be negative. So, the width of the rectangle is 7 meters.

The length

2(7) - 4

14 - 4 = 10 meters

Find attached an image of a rectangle. A similar question was answered here: https://brainly.com/question/23848042?referrer=searchResults