Respuesta :

Solution:

we have been asked to Use the equation tool to complete the table .

The given equation is [tex] y=-670+33x [/tex]

As we can see the Table is already filled , just one place need to fill.

So we will substitute the value of x from the table in the given equation and we will work out the value of y.

From table we have x=45.

[tex]  y=-670+33*45\\ \\ y=-670+1485\\ \\ y=815\\ [/tex]

Hence required value for the blank space in the table is 815.



Real Question :

Now Try Working With A New Function.

Use The Equation Tool To Complete Both Tables.

[tex]\left[\begin{array}{ccc}Table A\\x&y\\25&155\\30&320\\35&485\\40&650\\45&?\end{array}\right][/tex] [tex]\left[\begin{array}{ccc}Table B\\x&y\\40&650\\41&683\\42&716\\43&749\\44&?\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}y=-670+33(25)\\y=-670+33(30)\\y=-670+33(35)\\y=-670+33(40)\\?=-670+33(45)\end{array}\right] [/tex] [tex]\left[\begin{array}{ccc}y=-670+33(40)\\y=-670+33(41)\\y=-670+33(42)\\y=-670+33(43)\\?=-670+33(44)\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(45)\end{array}\right][/tex] Plug It In [tex]\left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(44)\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}33(x)Or33(45)\\1485\end{array}\right][/tex] Multiply [tex]\left[\begin{array}{ccc}33(x)Or33(44)\\1452\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}y=-670+1485\\y=815\end{array}\right][/tex] Simplify [tex]\left[\begin{array}{ccc}y=-670+1452\\y=782\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(45)\\y=-670+1485\\y=815\end{array}\right][/tex] Answers [tex]\left[\begin{array}{ccc}y= -670 + 33 (x)\\y = -670 + 33 (44)\\y = -670 +1452\\y=782\end{array}\right][/tex]