Answer:
[tex]2.4\cdot 10^{10} N/C[/tex]
Explanation:
The electric force exerted on a charge due to an electric field is given by:
[tex]F=qE[/tex]
where
q is the magnitude of the charge
F is the magnitude of the force
E is the magnitude of the electric field
In this problem, we have:
[tex]q=1.25\cdot 10^{-19}C[/tex] is the charge
[tex]F=3.0\cdot 10^{-9} N[/tex] is the magnitude of the force
using these data and re-arranging the equation, we can calculate the magnitude of the electric field:
[tex]E=\frac{F}{q}=\frac{3.0\cdot 10^{-9} N}{1.25\cdot 10^{-19} C}=2.4\cdot 10^{10} N/C[/tex]
