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Let the smallest number among them is n then next two consecutive even terms are: n+2 and n+4

The sum of numbers is 42, so:

↪n+n+2+n+4=42
↪3n+6=42
↪3n=42-6
↪n=36/3
↪n=12

The largest among these numbers is :
n+4
=12+4
=16↪Answer
Define x:

Let the smallest number be x
The other 2 numbers are x+2 and x+4

Construct Equation:

Sum of the numbers is 42
⇒x + (x + 2) + (x + 4) = 42

Solve for x:

x + (x + 2) + (x + 4) = 42

Remove brackets:
x + x + 2 + x + 4 = 42

Combine like terms:
3x + 6 = 42

Subtract 6 from both sides:
3x = 36

Divide both sides by 3:
x = 12

Find largest number:

The largest number = x + 4  = 12 + 4  = 16

Answer: The largest number is 16.

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