Respuesta :

Total number of possible outcomes = 36

Total number of outcomes with a sum of 12 = 1
{6,6)

Total number of outcomes with a sum of 3 = 2
{1,2}{2,1}

P(12 first, then 3) = (1/36)(2/36) = 1/648

Answer: The probability is 1/648

[tex] |\Omega|=6^2\cdot6^2=1296\\
|A|=1\cdot2=2\\\\
P(A)=\dfrac{2}{1296}=\dfrac{1}{648}\approx0.2\% [/tex]