Respuesta :
Answer:
Midpoint is (3.5, 2)
Step-by-step explanation:
the midpoint of the line segment whose endpoints are (5, 2) and (2, 2)
To find midpoint of two end points we use formula
[tex](\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})[/tex]
(5, 2) , x1 = 5 and y1= 2
(2,2), x2=2 and y2= 2
Plug in all the values and find the midpoint using the formula
[tex](\frac{5+2}{2},\frac{2+2}{2})[/tex]
[tex](\frac{7}{2},\frac{4}{2})[/tex]
(3.5, 2)
So midpoint is (3.5,2)
Answer:
The abscissa of obtained mid point is 3.5
Step-by-step explanation:
We are given the following information in the question:
Endpoints of a line segment are (5, 2) and (2, 2).
Mid point formula:
[tex](x,y) = \bigg(\displaystyle\frac{x_1+x_2}{2}, \displaystyle\frac{y_1+y_2}{2}\bigg)[/tex]
where (x,y) is the mid point and [tex](x_1,y_1),(x_2.y_2)[/tex] are the ends of line segment.
Putting the values:
[tex](x,y) = \bigg(\displaystyle\frac{5+2}{2}, \displaystyle\frac{2+2}{2}\bigg) = (3.5,2)[/tex]
The abscissa is the x coordinate of the point.
The abscissa of obtained mid point is 3.5
