Answer:
(D)
Step-by-step explanation:
The given vector is [tex](6,-3)[/tex], the magnitude of the given vector is gievn as:
[tex]m=\sqrt{(x)^2+(y)^2}[/tex]
Putting [tex]x=6[/tex] and [tex]y=-3[/tex], we get
[tex]m=\sqrt{(6)^2+(-3)^2}[/tex]
[tex]m=\sqrt{36+9}[/tex]
[tex]m=\sqrt{45}[/tex]
[tex]m=3\sqrt5[/tex]
Thus, the length of the given vector is [tex]3\sqrt5[/tex] units.
Therefore, option D is correct.
