we know that
the formula to solve the quadratic equation is
x={-b(+/-)√[b²-4ac]}/2a
we have
2a²-30a+108=0
where
a=2
b=-30
c=108
x={30(+/-)√[30²-4*2*108]}/(2*2)
x={30(+/-)√[36]}/(4)
x={30(+/-)6}/(4)
x1=(30+6)/4----> 36/4----> 9
x2=(30-6)/4----> 24/4----> 6
the answer is
the values of a are
a1=9
a2=6
