Respuesta :
The volume that would be occupied by 0.25 moles sample of H2 is calculated using ideal gas equation formula
that is PV =nRT
P(pressure)= 1.7 atm
V( volume)?
n(number of moles)= 0.250 moles
R(gas constant)=0.0821 l.atm/mol.K
T (temperature in kelvin)=35+273 = 308k
by making V the subject of the formula V=nRT/P
=(0.250 moles x 0.0821 L.atm/k.mol x 308 k)/( 1.70 atm) = 3.7 L of H2 gas
that is PV =nRT
P(pressure)= 1.7 atm
V( volume)?
n(number of moles)= 0.250 moles
R(gas constant)=0.0821 l.atm/mol.K
T (temperature in kelvin)=35+273 = 308k
by making V the subject of the formula V=nRT/P
=(0.250 moles x 0.0821 L.atm/k.mol x 308 k)/( 1.70 atm) = 3.7 L of H2 gas
A 0.250 mole sample of Hydrogen gas occupy 3.7 L volume , if it had a which has a pressure of 1.70 atm, and a temperature of 35 °c
Gas volume formula,
[tex]\rm \bold { V=\frac{nRT}{P} }[/tex]
Where,
n - number of moles = 0.250 moles
R - gas constant =0.0821 L.atm/mol.K
T - temperature in kelvin = 35+273 = 308k
P - pressure = 1.7 atm
Put the value in the formula we get
V = 3.7 L
Hence, we can conclude that a 0.250 mole sample of Hydrogen gas occupy 3.7 L volume , if it had a which has a pressure of 1.70 atm, and a temperature of 35 °c
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