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The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?

Respuesta :

First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is  (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number), 
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131
gracebrumbry

Answer:

x + 2x+7 + x- 12 = 131

Step-by-step explanation:

i did the test

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