jessblue77
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Which could be the initial point of vector u if it has a magnitude of 17 and the terminal point (3,13)?

a. (-5,-2)
b. (-5,2)
c. (5,-2)
d. (5,2)

Respuesta :

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -5 &,& -2~) % (c,d) &&(~ 3 &,& 13~) \end{array}\\\\\\ % distance value d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ||u||=\sqrt{[3-(-5)]^2+[13-(-2)]^2}\implies ||u||=\sqrt{(3+5)^2+(13+2)^2} \\\\\\ ||u||=\sqrt{64+225}\implies ||u||=\sqrt{289}\implies ||u||=17[/tex]
okpalawalter8

The initial point of the vector is mathematically given as

p1=(-5,-2)

Option A is correct

Which could be the initial point of vector?

Question Parameter(s):

if it has a magnitude of 17 and the terminal point (3,13)

Generally, the two points  is mathematically given as

p1=(-5,-2)

p2=(3,13)

Therefore

[tex]d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2[/tex]

Therefore

[tex]||u||=\sqrt{[3-(-5)]^2+[13-(-2)]^2} \\\\||u||=\sqrt{(3+5)^2+(13+2)^2} \\\\[/tex]

||u||=17

In conclusion,the  magnitude

||u||=17

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