The length of a rectangle is 3 inches longer then twice its width, where w is the width of the rectangle the area of the rectangle is 90 square inches. Write an equation that represents the area and find the width and length of the rectangle.

Respuesta :

A = w(2w + 3)
90 = 2w^2 + 3w
2w^2 +3w - 90 = 0
(w-6)(2w+15) = 0        (TRINOMIAL FACTORING)
w = 6 inch                   ( it can't be -15/2 because lengths can't be negative)
l = 2w + 3
  = 15 inch

The equation which represent the area of rectangle is [tex]2w^{2} +3w=90[/tex] and the width of the rectangle is 6 inches.

What is area?

The area is the amount of space within the perimeter of a 2D shape.

Formula for area of rectangle

area of rectangle = length × width

According to the given question

we have

width of the rectangle is w

length of the rectangle = 3+2w

area of rectangle = 90 square inches.

Therefore,

An equation that represents the area

area of rectangle =  length × width

⇒ 90 = (3+2w)×w

⇒ 90 = [tex]3w+2w^{2}[/tex]

or [tex]2w^{2}+3w=90[/tex] represents the equation for area.

For width,

solve the above equation

[tex]2w^{2} +3w-90=0[/tex]

[tex]2w^{2}+15w-12w-90=0[/tex]

[tex]2w^{2} -12w+15w-90=0[/tex]

[tex]2w(w-6)+15(w-6)=0[/tex]

[tex](2w+15)(w-6)=0[/tex]

[tex]w=6,\frac{-15}{2}[/tex]

Hence, the width of rectangle is 6inches.

( [tex]\frac{-15}{2}[/tex]  is not possible because with will never be negative)

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