Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer?

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keshavgandhi04 keshavgandhi04 · Answer 2 · 2022-03-08T06:24:24+01:00

The price at which two boys will purchase the computer will be $433.87.

It is given that the first boy had 7/8 of the price of the computer

The second boy had 5/6 of the money the first had.

Also together they had $696.00 more than they need to pay.

What will be the price of the computer?

For finding the price of the computer let us suppose the price of the computer is $ X.

So the first boy had 7/8 of the price of the computer = 7/8

the second boy had 5/6 of the money the first had =5/6* 7/8 X=35/48X

Both boys have = 7/8X+35/48X=696

By solving the above equation we will get the value of X=$433.87 which will be the cost of the computer.

Thus the price of the computer purchased by both the students will be $433.87

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