Given that C(x)=x³+800, where x is the number of deliveries per day. If it is necessary to keep cost below $1885, the greatest number of deliveries that can be made to achieve this goal will be found as follows:
for cost to remain at $1885 we shall have:
1885=x³+800
solving for x we shall have:
1885-800=x³
1085=x³
getting the cube root of both sides we shall have:
∛1085=(∛x³)
x=10.276
thus the number of trips should be at most 10 trips
