Three brothers have ages that are consecutive even integers the product of the first & third boys ages is 20 more than twice the seconds boy age.find the age of each of the boys
Let's say X is the first brother's age x+2 is second brother, and x+4 is the third brother Since the product of the first and third boy x(x+4) is 20 more than twice (20+x(x+2), our equation is x(x+4)=20+2(x+2) Simplify from there and see what you get.
