An object has a weight of 100 N on the surface of the Earth. If the object is moved to 2RE above the surface of the Earth, its weight is
25.0 N.

11.0 N.

0 N.

100 N.

Respuesta :

Weight of the object is defined as

[tex]W = mg[/tex]

here

m = mass of object

g = acceleration due to gravity

now at the surface of earth

[tex]g = \frac{GM}{R_e^2} [/tex]

so given that

[tex]mg = 100 N[/tex]

now when it is moved to distance 2Re from the surface so its distance from the center of earth will be given as Re + 2Re = 3Re

so acceleration due to gravity will be given as

[tex]g' = \frac{GM}{(3R_e)^2} = \frac{GM}{9R_e^2}[/tex]

so now weight is given as

[tex]W = m*\frac{g}{9}[/tex]

[tex]W = \frac{100}{9} = 11.1 N[/tex]

so now weight will be 11 N