In a kite, the diagonals intersect normally. Hence, we also know that XV= 4cm, half of XZ. This is because the triangle XVY and XVW are equal, but it is a general property of kitest. XVY is the right angle in this. We can use then trigonometry to calculate VY.
We have that tan30= opposite site of angle XYV/adjacent leg by the definition of the tangent. Hence tan30= XV/YV. Thus, substituting the value of the tangent:
[tex] \frac{1}{ \sqrt{3} } =XV/VY \\ VY= \sqrt{3} *XV=4 \sqrt{3} cm[/tex]
