Answer: Equivalent expression is 3+2k.
Step-by-step explanation:
Since we have given that
[tex]\dfrac{1}{5}(15+10k)[/tex]
As we have to use "Distributive property":
[tex]a\times (b+c)=a\times b+a\times c[/tex]
So, it becomes
[tex]\dfrac{1}{5}(15+10k)\\\\=\dfrac{1}{5}\times 15+\dfrac{1}{5}\times 10k\\\\=\dfrac{15}{5}+\dfrac{10k}{5}\\\\=3+2k[/tex]
Hence, equivalent expression is 3+2k.
