realgs6458
contestada

if i have 5.6 liters of gas in a piston at a pressure of 1.5 atm and compress the gas until its volume is 4.8 L, what will the new pressure inside the piston be?

Respuesta :

P(1)*V(1)=P(2)*V(2)
1.5 atm*5.6 L= P(2)*4.8 L
P(2)= 1.5 atm*5.6 L/4.8 L =1.75 atm
nuhulawal20

At constant temperature, if the volume of the sample of gas decreases to the given value, the pressure increases to 1.75atm.

What is Boyle's law?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

  • Initial volume of the gas V₁ = 5.6L
  • Initial pressure P₁ = 1.5atm
  • Final volume of the gas V₂ = 4.8L
  • Final pressure of the gas P₂ = ?

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = ( 1.5atm × 5.6L ) / 4.8L

P₂ = 8.4Latm / 4.8L

P₂ = 1.75atm

Therefore, at constant temperature, if the volume of the sample of gas decreases to the given value, the pressure increases to 1.75atm.

Learn more about Boyle's law here: brainly.com/question/1437490

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