a sample contains 36g of a radioactive isotope. how much radioactive isotope remains in the sample after 3 half-lives

Respuesta :

After 1st half life it will be 36/2 i.e. 18gm then 9 gm and then 4.5 grams simply
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Answer:

4.5 g

Explanation:

N0 = 36 g, Let half life is T.

t = 3 T, n is number of half lives = t / T = 3

By using the decay law of radioactivity

N / N0 = (1 / 2)^n

where, N0 be the initial amount

N be the amount left

n be the number of half lives

N / 36 = (1/2)^3

N / 36 = 1 / 8

N = 36 / 8 = 4.5 g