Answer:
The vertical component of the velocity is about 16 m/s.
Explanation:
The vertical component is the magnitude of the velocity reduced by the sinus of the angle 53 degrees. So
[tex]v_y = |v|\cdot \sin 53^\circ = 20.0 \frac{m}{s}\cdot 0.7986 \approx 16.0 \frac{m}{s}[/tex]
